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ax which tth |
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Answer» Compare x² - 2px + 1 = 0 with ax² + bx + c = 0., a = 1 , b = - 2p , c = 1 , If roots are not real then discreaminant < 0 b² - 4ac < 0 ( - 2p )² - 4 × 1 × 1 < 0 4p² - 4 < 0 4p² < 4 p² < 4/4 p ² < 1 p < ± 1 Therefore , If p < ±1 then the equation has no real roots. Like my answer if you find it useful! |
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