awlen field is 5yo. and th s ides aro s5:17; 12 Find Harar ac k tot na

1.	awlen field is 5yo. and th s ides aro s5:17; 12 Find Harar ac k tot nale . Albo ,thdHac ěŹë¤ho tio
Answer» GIVEN : The perimeter of a triangular field = 540m Let the sides are 25x , 17x , 12 x Perimeter of a ∆ = sum of three sides 25x + 17x + 12x = 540 54x = 540 x = 10 1st side (a) - 25x = 25×10= 250m 2nd side(b)= 17x = 17×10= 170m 3rd side (c)= 12x = 12 × 10 =120m Semi - perimeter ( S) = a+b+c/2 = (250 + 170+120)/2 = 540/2 = 270 m Area of the ∆= √ S(S - a)(S - b)(S - c) [By Heron’s Formula] = √ S(S - 250)(S - 170)(S - 120) = √ 270(270 - 250)(270 - 170)(270 - 120) = √ 270× 20×100×150 = √ 81000000 Area of the ∆= 9000 m² Cost of ploughing the field = (10/18.80) ×9000 = 4787 rupees

awlen field is 5yo. and th s ides aro s5:17; 12 Find Harar ac k tot nale . Albo ,thdHac ěŹë¤ho tio

Answer»

GIVEN : The perimeter of a triangular field = 540m

Let the sides are 25x , 17x , 12 x

Perimeter of a ∆ = sum of three sides

25x + 17x + 12x = 540

54x = 540

x = 10

1st side (a) - 25x = 25×10= 250m

2nd side(b)= 17x = 17×10= 170m

3rd side (c)= 12x = 12 × 10 =120m

Semi - perimeter ( S) = a+b+c/2

= (250 + 170+120)/2 = 540/2 = 270 m

Area of the ∆= √ S(S - a)(S - b)(S - c)

[By Heron’s Formula]

= √ S(S - 250)(S - 170)(S - 120)

= √ 270(270 - 250)(270 - 170)(270 - 120)

= √ 270× 20×100×150

= √ 81000000

Area of the ∆= 9000 m²

Cost of ploughing the field = (10/18.80) ×9000 = 4787 rupees