Average velocity of a particle performing shm in one time period is?

1.	Average velocity of a particle performing shm in one time period is?
Answer» SIMPLE harmonic motion can be expressed as follow: y=acos(Wt) where w is angular acceleration and w=2pi/T So, when we differentiate the above equation we get expression of VELOCITY given by: v=-awsin(wt) For a complete TIME period, t=T So, The average velocity= -aw(average of sin(w*t) over time period T) Average of Sin function over a complete cycle=0 Therefore, The average velocity of a particle performing S.H.M. in one time period is 0.

Answer»

SIMPLE harmonic motion can be expressed as follow:

y=a*cos(W*t) where w is angular acceleration and

w=2*pi/T

So, when we differentiate the above equation we get expression of VELOCITY given by:

v=-a*w*sin(w*t)

For a complete TIME period,

t=T

So,

The average velocity= -a*w*(average of sin(w*t) over time period T)

Average of Sin function over a complete cycle=0

Therefore,

The average velocity of a particle performing S.H.M. in one time period is 0.

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Average velocity of a particle performing shm in one time period is?

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