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Avagadro number of helium atoms have a mass of 1)2g 2)4g 3)8g 4)4*6.02*10^23 |
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Answer» atomic MASS of helium is 2 G THEREFORE no.of na or avagadro number is 6.022×10^234g=2x6.022*10^238g=4×6.022×10^23and the LAST one is itself a AVOGADRO no. |
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