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ATV tower has a height of 100m. How much population is covered by TV broadcast. If the average population density around the tower is `1000 km^(-2)` ? (radius of earth =`6.4xx10^(6)m`)A. `10^(3)`B. `10^(6)`C. `4xx10^(6)`D. `4xx10^(9)` |
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Answer» Here, h=100, population density `p=1000km^(-2)` `=(1000)/((1000)^(2)m^(2))=10^(-3)m^(-2)` Radius of the area covered by T.V. Broadcast `d=sqrt(2Rh)` Population covered=Area of rangexxpopulation density `pi d^(2)xxp=pi(2Rh)xxp` `=3.14xx[2xx(6.4xx10^(6))xx100]xx10^(-3)` `=40.12xx10^(5)cong4xx10^(6)` |
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