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Atoms present in 0.1 mole of so2 |
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Answer» HEYA USER , Here is your answer !! No. of atoms PRESENT in 1 mole of any SUBSTANCE = 6.022 * 10^23 Therefore , no. of atoms present in 1 mole of SO2 = 6.022 * 10^23 atoms . So, no. of atoms present in 0.1 mole of SO2 = 6.022 * 10^22 atoms . HOPE it helps !! |
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