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Atoms of element B form hcp lattice and those of the element A occupy 2//3^(rd) of tetrahedral voids. What is the formula of the compound formed by the elements A and B ? |
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Answer» Solution :The ATOMS of element B is forming close packed STRUCTURE. Let number of B atoms = n The total number of tetrahedral voids = 2n Atoms A OCCUPY `(2//3)^(rd)` of tetrahedral voids. Hence, the total number of Atoms = `2n xx 2/3 =(4n)/3` So the formula of a compound A`((4n)/3),B_n` Taking n = 3, we GET `A_4B_3`. |
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