1.

Atomic no. of N is 7, the atomic no. of IVth member of nitrogen family will be

Answer»

23
51
33
43

Solution :`IV^(th)` MEMBER will be in 5th PERIOD.
`therefore` Atomic number `=overset"II"7+overset"III"8+overset"IV"18+overset"V"18 =51`


Discussion

No Comment Found