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`AtoB` (zero order reaction) `CtoD` (first order reaction) In first order reaction gets `75%` completed in 40 min and zero order reaction gets `75%` completed in 30 min then calculate the value of Z where `Z=("Half life period of first order reaction")/("Half life period of zero order reaction")` |
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Answer» Correct Answer - 1 `Z=(((t_((3)/(4)))/(2))1^(st) "order")/(((2t_((3)/(4)))/(3))"zero order")` `=((40)/(2))/(((2xx30)/(3)))=1.0` |
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