1.

At what temperature would CO_(2) molecule have an rms speed equal to H_(2) at 27^(@) C.

Answer»

`4400 K`
`2200 K`
`6600K`
`1100 K`

Solution :`rms_(CO_(2)) = rms_(H_(2))`
`(sqrt((3RT)/(M)))_(CO_(2)) = (sqrt((3RT)/(M)))_(H_(2))`
`(3 xx R xx T)/(44) = (3 xx R xx 300)/(2)`
`T = 6600 K`


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