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At what temperature will the root mean square velocity of SO2 be same as that of methane at 27°C? |
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Answer» Crms = \(\sqrt{\frac{3RT}{M}}\) For CH4, M = 16, T = 300 K Crms = \(\sqrt{\frac{3R\times300}{16}}\) For SO2, M = 64, T = ? Crms = \(\sqrt{\frac{3R\times T}{64}}\) \(\sqrt{\frac{300}{16}}=\sqrt{\frac{T}{64}}\) T = \(\frac{300\times64}{16}\) = 1200 t = 1200 - 273 = 927ºC. |
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