1.

At what temperature will the root mean square velocity of SO2 be same as that of methane at 27°C?

Answer»

Crms \(\sqrt{\frac{3RT}{M}}\)

For CH4, M = 16, T = 300 K

Crms = \(\sqrt{\frac{3R\times300}{16}}\)

For SO2, M = 64, T = ?

Crms = \(\sqrt{\frac{3R\times T}{64}}\)

\(\sqrt{\frac{300}{16}}=\sqrt{\frac{T}{64}}\)

T = \(\frac{300\times64}{16}\)

= 1200

t = 1200 - 273

= 927ºC.



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