1.

At what temperature, will the rms velocity of a gas at 50^(@)C be doubled ?

Answer»

626K
1019K
`200^(@)C`
`1019^(@)C`

Solution :`u_("r.m.s.") = SQRT((3RT)/( M)):. u_("r.m.s.") prop sqrt( T )`
For `u_("r.m.s.") ` to be doubled, temperature must be raised by 4 TIMES.
`T = ( 50 + 273 )K = 323 K`
`:. 4T = 4 xx 323 K = 1292K`
`= ( 1292 - 273) C = 1019^(@)C`


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