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At what temperature will hydrogen molecules have the same root mean square speed as nitrogen molecules at `27^(@)C` ? |
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Answer» `sqrt((3RT)/(M_(H))) = sqrt((3R xx 300)/(M_(N)))` or `(T)/(M_(H)) = (300)/(M_(N)) " or " T = (300)/(28) xx 2 = 21.43 K` |
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