At what temperature is average speed of gas molecule will be double th

1.	At what temperature is average speed of gas molecule will be double than that at 27
Answer» ANSWER: Explanation: ANSWER: We KNOW, Average speed, V=√(8RT/πM). At 27 C. V1= √(8R27/πM). Let V2 be the speed which is DOUBLE of V1 so, V1/V2=√(8RT/πM)/√(8R27/πM). 1/2=√27/√T2. Squaring on both the sides we get, T2=27*4. T2=108 C.

At what temperature is average speed of gas molecule will be double than that at 27

Answer»

Explanation:

ANSWER:

Average speed,

V=√(8R*T/πM).

At 27 C.

V1= √(8R*27/πM).

Let V2 be the speed which is DOUBLE of V1 so,

V1/V2=√(8R*T/πM)/√(8R*27/πM).

1/2=√27/√T2.

Squaring on both the sides we get,

T2=27*4.

T2=108 C.