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At what temperature 128 g of SO2 confined in vessel of 5 dm3 capacity will exhibit a pressure of 10.0 bar? Given a = 6.7 bar L2 mol-2 and b= 0.0564 L mol-1 |
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Answer» w = 128 g V = 5 dm3 P = 10.0 bar MSO2 = 64 g n = w/M = 128/64 = 2 Putting values in equation : ( P + an2 /V2 ) (V – nb) = nRT We get T = 329 K |
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