1.

At what temperature 128 g of SO2 confined in vessel of 5 dm3 capacity will exhibit a pressure of 10.0 bar? Given a = 6.7 bar L2 mol-2 and b= 0.0564 L mol-1 

Answer»

w = 128 g

 V = 5 dm3 

P = 10.0 bar 

MSO2 = 64 g 

n = w/M = 128/64 = 2 

 Putting values in equation : ( P + an2 /V2 ) (V – nb) = nRT 

We get T = 329 K



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