1.

At what separation should two equal charges, 1.0c each be placed so that the force between them equals the weight of a 50kg person?

Answer»

Answer:

4242.6m

Explanation:

F=mg=50kg×10m/s^2=500N

F=Kq^2/r^2

r^2=9×10^9×1×1/500

r^2=4242.6

or

4.2426×10^3



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