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At what separation should two equal charges, 1.0c each be placed so that the force between them equals the weight of a 50kg person? |
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Answer» Answer: 4242.6mExplanation: F=mg=50kg×10m/s^2=500N F=Kq^2/r^2 r^2=9×10^9×1×1/500 r^2=4242.6or 4.2426×10^3 |
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