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At what point on the parabola `y^2=4x`the normal makes equal angle with the axes?`(4,4)`(b) `(9,6)`(d) `(4,-4)`(d) `(1,+-2)`A. (4,4)B. (9,6)C. (4,-4)D. `(1,pm2)` |
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Answer» Correct Answer - D (4) We have a=1. Normal at `(m^(2),-2m)" is "y=mx-2-m^(3)` Given that normal makes equal angle with the axes, its slope is `m=pm1`. Therefore, point P is `(m^(2),-2m)-=(1,pm2)`. |
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