1.

At what point on the parabola `y^2=4x`the normal makes equal angle with the axes?`(4,4)`(b) `(9,6)`(d) `(4,-4)`(d) `(1,+-2)`A. (4,4)B. (9,6)C. (4,-4)D. `(1,pm2)`

Answer» Correct Answer - D
(4) We have a=1.
Normal at `(m^(2),-2m)" is "y=mx-2-m^(3)`
Given that normal makes equal angle with the axes, its slope is `m=pm1`.
Therefore, point P is `(m^(2),-2m)-=(1,pm2)`.


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