At what height, the value of g is same as at a depth ofR/2 ?

1.	At what height, the value of g is same as at a depth ofR/2 ?
Answer» Solution :At depth ` = R/2` , value of acceleration due to gravity , ` G. = g (1 - ( R )/(2R) ) = g/2` At HIGHT X` g. = g (1 - (2x)/(R ) )` ` therefore g (1 - (2x)/( R) ) = g/2` ` 1/2 = (2x)/( R ) rArr x = R/4`

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