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At what height from the surface of Earth the gravitational force will be reduced by 10% if the radius of Earth is 6400 km? |
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Answer» SOLUTION :Gravitational FORCE on the Earth surface `F_(s)=(GMm)/(R_(E)^(2))` Gravitational force at HEIGHT h `F_(h)=(GMm)/((R_(E)+h)^(2))` `THEREFORE(F_s)/(F_h)=((R_(E)+h)^(2))/(R_(E)^(2))=(10)/(9)` `3(R_(E)+h)=3.162R_(E)` `3h=(3.162-3)R_(E)` `=0.162R_(E)` `(R_(E)+h)/(R_E)=(3.162)/(3)` `therefore` Height h `=(0.162xx6400)/(3)` (or) h = 345.6 KM |
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