1.

At what distance from a concave mirror of focal length 10 cm should an object 2cm long be placed in order to get an erect image 6cm tall?​

Answer» ONG>ANSWER:

We know magnification=

height of the image

height of the object

Also, magnification=

object DISTANCE

−image distance

−

U

V

=

h

0

h

i

=

2

6

=3

−V=3U

From,

f

1

=

V

1

−

U

1

10

−1

=

−3U

1

+

U

1

10

−1

=

3U

2

⟹−10=

2

3U

⟹U=

3

−20

=6.7m


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