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At what concentration of copper sulphate solution , the potential of Cu^(2+), Cu becomes zero? The standrd reduction potential of Cu^(2+), Cu is 0.34 V. |
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Answer» Solution :`E = E^@ + (0.059)/n log C "(or)" 0 = 0.34 + (0.059)/2 log [Cu^(2+)]` `0.0295 log [Cu^(2+)] = -0.34 " (or) " log [Cu^(2+)] = -(0.34)/(0.0295) = -11.57` CONCENTRATION of `CuSo_4 = 10^(-11.57) = 10^(-12 + 0.43) = 2.9 xx 10^(-12)M`. |
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