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At what angle should a cyclist lean over from the vertical while negotiating a curve of radius 58m with a speed of 15 km/hour? |
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Answer» The angle of banking is given by, tanθ = \(\frac {v^2}{rg}\) Here, v = \(\frac {15000}{60 \times 60} \) = 4.17 ms-1 ∴ tanθ = \(\frac {(4.17)^2}{58 \times 9.8}\) = 0.03059 θ = tan-1 (0.03059) = 1°45’. |
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