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At what altitude (h) above the earth's surface wouldthe acceleration due to gravity be one fourth of itsvalue at the earth's surface?(1) h = R(2) h = 4R(3) h = 2R(4) h = 16R |
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Answer» h=R Explanation:g'=g/4 By RELATION g'=g/ (1+h/r)^2 g/4=g/ (1+h/r)^2 By SOLVING we get h=R |
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