1.

At what altitude (h) above the earth's surface wouldthe acceleration due to gravity be one fourth of itsvalue at the earth's surface?(1) h = R(2) h = 4R(3) h = 2R(4) h = 16R​

Answer»

ANSWER:

h=R

Explanation:g'=g/4

By RELATION

g'=g/ (1+h/r)^2

g/4=g/ (1+h/r)^2

By SOLVING we get

h=R



Discussion

No Comment Found

Related InterviewSolutions