1.

At whar temparaturethe kinetic energy of a molecule will be 1.0ev

Answer»

kT1eV=1/2kT1eV=1.5kT1eV/1.5k=TT=1eV/1.5kT=1(1.6×10^-19)(1)/1.5(8.6×10^-5)T=7752 KELVIN



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