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At the two ends of a light string, passing over a stationary, light, smooth pulley, two masses m and 2m are attached. Length of the string on either side of the pulley was the same initially, and the two masses were at a height of 13.08. After the system is released, what will be the velocities of the two masses when the mass m rises by 6.54m? At that moment, if the string snaps suddenly, find the time taken by the masses to reach the ground. |
| Answer» SOLUTION :VELOCITY of each 6.54 m`CDOT s^(-1) ,t_(1) = 2.77 s, t_(2) = -0.67 `s | |