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At the top of a mountain, a thermometer reads 7^(0)Cand a barometer reads 70 cm of Hg. At the bottom of tlie ,nowuain, they read 27^(0)C and 76 cm of Hg respectively.Compare the density of air at tlu top with that at the bottom of the mountain. |
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Answer» Solution :At the top of the mountain, PRESSURE `P_(1) = 70` cm of HG Temperature `T_(1) = 7 + 273` = 280 K DENSITY of the air = `d_(1)` Atthe bottom of the mountain, pressure `P_(2) ` = 76 cm of Hg Temperature `T_(2) = 27 + 273 = 300 ` K Density of the air `d_(2)` From the gas equation, `(P_(1))/(d_(1)T_(1)) = (P_(2))/(d_(2)T_(2)) " (or)" (d_(1))/(d_(2)) = (P_(1))/(T_(1)) xx (T_(2))/(P_(2)) = (70)/(280) xx (300)/(76)` = 0.9868. |
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