At the park , 50% of the vehicle parked were cars , 30% per motorcycle

1.	At the park , 50% of the vehicle parked were cars , 30% per motorcycles and the rest of the vehicles were vans. (i) if 40 cars left the car Park, what percent of vehicle parked their were cars.
Answer» Step-by-step explanation: Parking ⬇️ ____________________________________________ ⬇️ ⬇️ ⬇️ Cars. MOTOR Cycles. VANS (50%). (30%). (40) (i) Calculate the number of motorcycles parked there. Ans) Let the number of total vehicles be "x" % of Vans = 100% - (% of cars + % of motorcycles) => 100% - ( 50% + 30%) => 100% - 80% = 20% 20% of total vehicles = 40 vans 20% of x = 40 $\frac{20}{100}$ of x = 40 x = 40 × $\frac{100}{20}$ x = 200 Therefore , The number of Motorcycles = 30% of 200 = $\frac{30 \times 20}{100}$ = 60 (II)If 40 cars LEFT the car park, what percentage of the vehicles parked there were cars? Ans) Number of cars = 50% of 200 = $\frac{50 \times 200}{100}$ = 100 cars % of cars = $\frac{number \: of \: cars \: remaining \times 100}{numbers \: of \: vehicles \: remaning}$ = $\frac{60 \times 100}{160}$ % = $\frac{75}{2}$ % = 37.5%

At the park , 50% of the vehicle parked were cars , 30% per motorcycles and the rest of the vehicles were vans. (i) if 40 cars left the car Park, what percent of vehicle parked their were cars.

Answer»

Step-by-step explanation:

Parking

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Cars. MOTOR Cycles. VANS

(50%). (30%). (40)

(i) Calculate the number of motorcycles parked there.

Ans) Let the number of total vehicles be "x"

% of Vans = 100% - (% of cars + % of motorcycles)

=> 100% - ( 50% + 30%)

=> 100% - 80%

= 20%

20% of total vehicles = 40 vans

20% of x = 40

$\frac{20}{100}$ of x = 40

x = 40 × $\frac{100}{20}$

x = 200

Therefore , The number of Motorcycles = 30% of 200

= $\frac{30 \times 20}{100}$

= 60

(II)If 40 cars LEFT the car park, what percentage of the vehicles parked there were cars?

Ans) Number of cars = 50% of 200

= $\frac{50 \times 200}{100}$

= 100 cars

% of cars = $\frac{number \: of \: cars \: remaining \times 100}{numbers \: of \: vehicles \: remaning}$

= $\frac{60 \times 100}{160}$ %

= $\frac{75}{2}$ %

= 37.5%