At temperaturee T. a copound AB_(2(g)) dossociates according to the reaction 2AB_(2(g))hArr2AB_((g))+B_(2(g)) with a degree of dissociation x, which is small compared with unity. The expression for K_(P), in terms of x and the total pressure. F is

At temperaturee T. a copound AB_(2(g)) dossociates according to the re

1.	At temperaturee T. a copound AB_(2(g)) dossociates according to the reaction 2AB_(2(g))hArr2AB_((g))+B_(2(g)) with a degree of dissociation x, which is small compared with unity. The expression for K_(P), in terms of x and the total pressure. F is
Answer» `(Px^(3))/(2)` `(Px^(2))/(2)` `(Px^(3))/(3)` `(Px^(2))/(2)` Solution :`2AB_(2(g))hArr2AB_((g))+B_(2(g))` `{:("Initially",1,0,0),("At EQULIBRIUM",(1-x),x, x//2):}` Total no. of moles at equlibrium `=(1-x)+x+x/2=(2+x)/(2)` Partial pressure = mole fraction `XX` total pressure APPLYING `K_(p)=(P_(AB)^(2)xxP_(B_(2)))/(P_(AB_(2))^(2))` `=((((x)/(1+x))/(2)xxP)^(2)xx(((x/2)/(a+x))/(2)xxP))/((((1-x)/(1+x))/(2)+P)^(2))=(Px^(3))/((2+x)(1-x)^(2))` Since `x ltlt1so(1-x)^(2)` can be neglected and (2+x) and be taken as 2. `thereforeK_(p)=(Px^(3))/(2)`