1.

At temperature of 298 K the emf of the following electrochemical cell Ag_((s)) |Ag^(+ )(0.1M ) ||Zn^(2+) (0.1 M )|Zn_((s)) willbe( givenE_("cell")^@=-1.562V)

Answer»

`-1.532`V
`-1.503 V`
`1.532 V`
`-3.06 V`

Solution :`2Ag _((s))TO2AG^(+)( 0.1 M )+ 2e^(-)`
`2e^(-)+Zn ^(2+)( 0.1M )toZn_((s))`
` 2Ag _((s)) +Zn^(2+) (0.1 M )toZn_((s))`
` 2Ag_((s)) +Zn^(2+) ( 0.1 M ) to2Ag ^( +) ( 0.1 M )+ Zn_((s))`
` thereforeE_("CELL ") =E_("cell")^(@ )- ( 0.059 1)/( 2 )log_(10)([AG^( +)]^2 )/([Zn^(2+)])`
` thereforeE_("Cell") = -1.562- ( 0.0591 )/(2)log_(10)((0.1 )^2)/( 0.1)`
`= -1.562- 0.03lpog_(10)10^(-1)`
` E_("cell") =-1.562+ 0.03=- 1.532V `


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