1.

At STP the volume of nitrogen gas required to covera sample of silica gas, assuming larngmulr monolayer adsorption is found to be 1.30 gcm^(-2) g^(-1) of the gel. The area occupied by a nitrogen molecule is 0.16nm^(2). What is the surface area per gram of silica gel ?

Answer»

`5.568m^(2)G^(-1)`
`3.48m^(2)g^(-1)`
`1.6m^(2)g^(-1)`
None of these

Solution :No. of MOLECULE PER gm of `N_(2)` in MONOLAYER `=(6xx10^(23))/(22400)xx1.30=3.48xx10^(19)`
area of a molecule `=1.6xx10^(19)m^(2)`
`:.""` Area covered by molecule per gram`=3.48xx10^(19)xx1.6xx10^(-19)=5.568m^(2)`
`:. ""`Surface are `=5.568m^(2)g^(-1)`


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