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At STP, a container has 1 mole of Ar, 2 mole of `CO_(2)`, 3 moles of `O_(2)` and 4 moles of `N_(2)`. Without changing the total pressure if one mole of `O_(2)` is removed, the partial pressure of `O_(2)`A. is changed by about 26 %B. is halvedC. is unchangedD. changes by 33 % |
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Answer» Correct Answer - 1 In the first case, `n_(Ar)=1,n_(CO_(2))=2, n_(O_2)=3 n_(N_(2))=4` `therefore "Total no. of moles"=1+2+3+4=10` If P in the total pressure, `P_(o_(2))=(3P)/(10)` In the second case, `n_(o_(2))=2,n_("total")=9` As P remains the same, `P_(o_(2))=(2P)/(9)` `therefore "Decreasc in Partial pressure of" CO_(2)` `=(3P)/(10)-(2P)/(9)=(7P)/(90)` `therefore "decrease in partial pressure of" CO_(2)` `=(7P//90)/(3P//10)xx100=(700)/(27)=26%` |
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