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At STP 56 CC of hydrogen sulphide is mixed with 60 CC of chlorine. Calculate the mass of Sulphur formed. ​

Answer» EXPLANATION:H2S+CL2=S+HClFirst find VOLUME at 1 am and 273kFor that there is a relationVolume at stp /22700 =volume at 1 atm and 273k /22400Volume /22400 = 0.00246Moles of h2s =0.00246Moles of cl2 = 0.00218Limiting ratio = 0.00218Moles of s formed = limiting ratio×coefficient =0.00218Mass of s formed = 0.07 GM


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