1.

At STP 1.12 litre of H_(2) is obtained on flowing current for 965 seconds in a solution . The value of current is

Answer»

10 Amp.
1.0 Amp.
1.5 Amp.
2.0 Amp.

Solution :1.12 LITRE of `H_2` at STP =0.1 g of `H_2`.
`therefore W =Zit`
`therefore I =(W)/(Zt) = (0.1 xx 96,500)/(Exxt) =(0.1xx96,500)/(1xx965) =10A`


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