1.

At STP 1.12 litre of H_(2) is obtained on flowing a current for 965 seconds in a solution . The value of current is

Answer»

10
1
1.5
2

Solution :`2H^(+)+underset(2"mole"2xx96500C)(2E^(-))rarrunderset("1mole"22.4"lt")(H_(2)`
To liberate 22.5 lt of `H_(2)` GAS, electricity REQUIRED
`=2xx96500C`
To liberate 1.12 lt of `H_(2)` gas, electricity required
`=(2xx96500xx1.12)/(965"sec")=10` ampere


Discussion

No Comment Found