1.

At STP 1.12 litre of H_(2) is obtained on flowing a current for 965 seconds in a solution. The value of current in amperes is

Answer»

10
`1.0`
`1.5`
`2.0`

Solution :`1.12 L H_(2) = 0.1 g eq. of H_(2)`
Q = 0.1 F = 9650 C .
HENCE , `I = (Q)/(t) = (9650)/(965) = 10 A` .


Discussion

No Comment Found