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At some point along a straight line, a person A has constant velocity of 10 m/s and a person B start from rest with acceleration at 2 m/s2. What can be the maximum distance by which A can be ahead of B.(Ans 25 m) |
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Answer» V²=u²+2as Given u=0 v=10m/s a=2m/s² s=? now 10²=0²+2*2*s 100=4s s=100/4 =25 m Max.Distance=25
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