1.

At same temperature and pressure, the rate of diffusion of hydrogen gas is 3 sqrt( 3) times that of a hydrocarbon having molecular formula, C_(n) H_(2n-2).The value of n is

Answer»

3
2
6
4

Solution :`( r ( H_(2)))/( "r ( HYDROCARBON)") = sqrt(("M(hydrocarbon)")/(M(H_(2))))`
`3 sqrt( 3) = sqrt(("M(hydrocarbon)")/(2))`
M ( hydrocarbon) = `(3sqrt( 3))^(2) xx 2 = 54 `
For `C_(N)H_(2n-2) .12N+(2n-2) = 54`
or n = 4


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