1.

At present Asha's age (in years) is 2 more than the square of her daughter Nisha's age.When Nisha grows to her mother's present age. Asha's age would be one year less than10 times the present age of Nisha, Find the present ages of both Asha and Nisha.

Answer»

Let Nisha's age is x years Aisha's age = (x² + 2) years

Now, A/C to question , when Nisha grows to her mother present age .means Nisha's growth = Aisha's present age - Nisha's present age = x² + 2 - x Then, this time Aisha's age = Aisha's present age + growing time = x² + 2 + x² + 2 - x = 2x² - x + 4

Now, question said , Aisha's age = 10× times of Nisha's age -1 2x² - x + 4 = 10x -1 2x² - 11x + 5 = 0 2x² -10x - x + 5 = 0x = 5 and 1/2 x ≠ 1/2 because age doesn't in moths

Hence , Nisha's present age = 5 years Aisha's present age = (5)² + 2 = 27 years



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