1.

At N.T.P. the volume of a gas is found to be 273 ml. What will be the volume of this gas at 600 mm Hg and 273^(@)C

Answer»

391.8 ml
380 ml
691.6 ml
750 ml

Solution :`V_(2)=(P_(1)V_(1))/(T_(1))(T_(2))/(P_(2))=(760)/(600)XX(546)/(273)xx273=691.6 ml`


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