1.

At identical temperature and pressure, the rate of diffusion of hydrogen gas is 3sqrt(3) times that of a hydrocarbon having molecular formula C_(n)H_(2n-2). What is the value of ?

Answer»

1
4
3
8

Solution :`r_(1)PROP1/(sqrt(M_(1))`or `(r_(1))/(r_(2))=sqrt((M_(2))/(M_(1)))`
Given `r_(1)=3sqrt(3)r_(2)IMPLIES(r_(1))/(r_(2))=sqrt((M_(2))/(M_(1)))=3sqrt(3)`
or `3sqrt(3)=sqrt((M_(2))/2)` `M_(2)=27xx2=54`
Now `12xxn+2n-2=54`
`14n=56\>n=4`


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