1.

At identical temperature and pressure, the rate of diffusion of hydrogen gas is 3 sqrt( 3) times that of a hydrocarbon having molecular formula C_(n) H_(2n-2). What is the value of n ?

Answer»

1
4
3
8

Solution :`(r_(H_(2)))/(r_("Hydrocarbon")) = SQRT((M_("Hydrocarbon"))/(M_(H_(2))) ) = 3sqrt(3)`
`:. sqrt((M_("Hydrocarbon"))/(2)) = 3 sqrt(3)`
`(M_("Hydrocarbon"))/(2) = 27`
`M_("Hydrocarbon") = 2 xx 27 = 54 `
`:. N = 4` and hydrocarbon is `C_(4) H_(6)`


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