1.

At constant temperature ,osmotic pressure of an aqueous solution of 1.5 M NH_(4)NO_(3) and x N Al_(2)(SO_(4))_(3) are equal, thenmention the value of X. ( Assume that ionic solid substances completely dissociates in the solution . )

Answer»

0.1
3.6
1.2
0.5

Solution :`n_(1)M_(1) = n_(2)M_(2)`
For`NH_(4)NO_(3)`VALUES of `n_(1)` and `M_(1)` are 2 and 1.5respectively
For `Al_(2)(SO_(4))_(2)n_(2) = 5 `
`:. M_(2) =( 2)/(5) xx 1.5 = 0.6 `
Normality of `Al_(2)(SO_(4))_(3)= 6 xx ` molarity `= 6 xx 0.6 = 3.6 N `


Discussion

No Comment Found