1.

At constant temperature , if pressure increases by 1% , the percentage decrease of volume is :

Answer»

`1%`
`100 //101%`
`1//101%`
`1//100%`

Solution :Let `P_(1) = 100` mm Hg
INCREASE in PRESSURE
`= 100 XX ( 1)/( 100) = 1 `
`p_(2) = 100 +1 = 101 mm Hg `
`V_(1) = V` and `V_(2) = ?`
`p_(1) V_(1) = p _(2) V_(2)`
or `V_(2) = ( p_(1) V_(1))/(p_(2)) = ( 100 xx V )/( 101) = ( 100)/( 101) V `
Decrease in volume`= ( V - ( 100)/( 101) V )/( V )`
` = V ( 1 - (100)/( 101))/( V ) = ( 1)/( 101)%`


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