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⠀⠀⠀⠀At constant temperature 200 cm³ of at 720 mm and 400 cm³ of at 750 mm pressure are put... |
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Answer» ect option is D 444 mm The number of MOLES of nitrogen n= RT PV
= RT 720×200
The number of moles of OXYGEN n ′ = RT PV
= RT 750×400
The FINAL pressure P= V nRT
= 1000 RT 720×200
+ RT 750×400
RT= 1000 144000+300000
=444 mm. oo ha AAPNE nahi kiya unfollow SORRY(◍•ᴗ•◍)❤(◍•ᴗ•◍)❤
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