1.

⠀⠀⠀⠀At constant temperature 200 cm³ of at 720 mm and 400 cm³ of at 750 mm pressure are put...​

Answer»

ect option is

D

444 mm

The number of MOLES of nitrogen n=

RT

PV

=

RT

720×200

The number of moles of OXYGEN n

=

RT

PV

=

RT

750×400

The FINAL pressure P=

V

nRT

=

1000

RT

720×200

+

RT

750×400

RT=

1000

144000+300000

=444 mm.

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