At constant pressure (∆P=0) Than, Enthalpy ∆H=∆U+∆(PV) ∆H=�

1.	At constant pressure (∆P=0) Than, Enthalpy ∆H=∆U+∆(PV) ∆H=∆U+P∆V+V∆P; But as (∆P=0) ∆H=∆U+P∆V But if the Volume is constant (∆V=0) Than the equation becomes ∆H=∆U+V∆P What does this Equation implies and what is it's application?
Answer» At constant pressure (∆P=0) Than, Enthalpy ∆H=∆U+∆(PV) ∆H=∆U+P∆V+V∆P; But as (∆P=0) ∆H=∆U+P∆V But if the Volume is constant (∆V=0) Than the equation becomes ∆H=∆U+V∆P What does this Equation implies and what is it's application?

At constant pressure (∆P=0) Than, Enthalpy ∆H=∆U+∆(PV) ∆H=∆U+P∆V+V∆P; But as (∆P=0) ∆H=∆U+P∆V But if the Volume is constant (∆V=0) Than the equation becomes ∆H=∆U+V∆P What does this Equation implies and what is it's application?

Answer»

At constant pressure (∆P=0)

Than, Enthalpy

∆H=∆U+∆(PV)

∆H=∆U+P∆V+V∆P; But as (∆P=0)

∆H=∆U+P∆V

But if the Volume is constant (∆V=0)

Than the equation becomes

∆H=∆U+V∆P

What does this Equation implies and what is it's application?