1.

At certain temperature 1.6% solution of an unknown substance is isotonic with 2.4 % solution of Urea. If both the solutions have the same solvent and both the solutions have same density 1 gm/cm^(3), what will be the molecular mass of unknown substance in gm/mol. [Mole mass of urea = 60 gm/mol]

Answer»

40
90
80
30

Solution :For, isotonic solution
`((% w//V)/(M))_("UREA")=((%w//V)/(M))_("unknown")`
`(2.4)/(60)=(1.6)/(M)`
`THEREFORE M=(1.6xx60)/(2.4)=40` gram/mole


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