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At any instant a current of 2 A is increasing at a rate of `1 A//s` through a coil of indcutance 2 H. Find the energy (in SI units) being stored in the inductor per unit time at that instant. |
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Answer» Correct Answer - 4 `U=1/2 Li^(2)` Energy stroed per unit time `(dU)/(dt) = 1/2 L2i (di)/(dt) =Li(di)/(dt) = 2 xx 2 xx 1 =4 J//s`. |
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