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At a point on groumd the angle of elevation of vertical tower is 30 degree found yo be tangent is 5/12 on walking 192 toward tower the tangent of elevation is 3/4. Find height of tower |
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Answer» ANSWER: 180m Step-by-step explanation: Let TR be the tower such that TR=X P and Q be the POINT on the ground such that tanθ= 12 5 and tanα= 4 3
And QR=y Given PQ=192m In right TRIANGLE TQR, tanα= QR TR = y x
⇒ 4 3 = y x
⇒y= 3 4 x...(1) In right triangle TPR, tanθ= PR TR
⇒ 12 5 = (y+192) x
⇒x= 12 5 (y+192)...(2) ⇒x= 12 5 ( 3 4 x+192) ⇒x= 9 5 x+80 ⇒x− 9 5 x=80 ⇒ 9 4 x=80 ⇒x= 4 9 (80)=180 Hence, the height of the tower is 180 m.
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