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At a place, the horizontal component of earth’s magnetic field is B and angle of dip is 60°. What is the value of horizontal component of the earth’s magnetic field at equator? [Delhi 2017]

Answer»

he horizontal component of electric field is GIVEN by B=Be COS (o)o is angle of dip Be is TEH NET magnetic field At o is 60°B=Be cos 60°B=Be ( 1/2) Be= 2Bhere Bis BHNow horizontal component at equator BH= Becos ( o)angle of dip at equator is 0BH= Be cos (0)=Be=2BBH=2B



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