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At a place, the horizontal component of earth's magnetic field is B and angle of dip is 60^@. What is the value of horizontal component of earth's magnetic field at equator? |
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Answer» Solution :`B_(H)=B_(E) cos delta` `B=B_(E)cos 60^(@)impliesB_(E)=2B` Aq equator `delta=0^(@)` `:.B_(H)=2Bcos0^(@)=2B` [Alternativ\ely, Award full one MARK, if student doesn't the value `(=2B)` of `B_(E)` while finding the value of horizontal component of equator, and just WRITES and formula only.] |
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